Reports

I would like to suggest an adaptation of @whereisalext's answer. By creating a dict of supported units with their respective sizes and then iterating from larger to smaller, the same behaviour can be achieved with less code:

def humanbytes(num_bytes: int) -> str:
    """Return the given bytes as a human friendly B, KB, MB, GB, or TB string."""
    units_map = {
        'TB': 2**40,
        'GB': 2**30,
        'MB': 2**20,
        'KB': 2**10,
        'B': 1,
    }
    # determine unit and factor
    for unit_name, unit_factor in units_map.items():
        if unit_factor <= num_bytes:
            break
    # build response
    return f'{float(num_bytes/unit_factor):.2f} {unit_name}'

Output:

1 == 1.00 B
1024 == 1.00 KB
500000 == 488.28 KB
1048576 == 1.00 MB
50000000 == 47.68 MB
1073741824 == 1.00 GB
5000000000 == 4.66 GB
1099511627776 == 1.00 TB
5000000000000 == 4.55 TB

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