We can break down the problem into two steps:

1. Length Comparison: The number with more digits is guaranteed to be larger. So, if one string is longer than the other, it is the larger number.
2. Lexicographical Comparison: If the two numbers have the same length, we can compare them lexicographically (i.e., just as we compare normal strings), because for two strings of the same length, the one that is lexicographically greater is the numerically greater number.

std::cout<<a.length()==b.length()?a>b:a.length()>b.length();