79203977

Date: 2024-11-19 15:18:29
Score: 1.5
Natty:
Report link

Thanks for your question! Such a channel is not (to our knowledge) physically possible, because this additional Hilbert space must have always existed.

It is not that your channel creates this Hilbert space, but that it maps a state which was originally confined to a subspace (i.e. $H_A$) to the entire space (i.e. $H_A\otimes H_B$).

Therefore, to construct this channel, represent your original state in this new, enlarged space (essentially by adding zeros), and define your Kraus operators over the same.

Reasons:
  • Blacklisted phrase (0.5): Thanks
  • Long answer (-0.5):
  • No code block (0.5):
  • Low reputation (1):
Posted by: marzchipane