79348412

Date: 2025-01-11 15:55:37
Score: 0.5
Natty:
Report link

In MVI, when state changes, by default all UI elements observing that state will be recomposed. However, there are several ways to optimize this:

  1. Use derivedStateOf for each list:

    data class ViewState( val students: List, val teachers: List )

    val studentsState = derivedStateOf { state.students } val teachersState = derivedStateOf { state.teachers }

    LazyColumn { items(studentsState.value) { student -> // This will only recompose when students list changes } }

  2. Split your state class and use multiple StateFlow:

class ViewModel { private val _studentsState = MutableStateFlow<List>(emptyList()) val studentsState = _studentsState.asStateFlow()

private val _teachersState = MutableStateFlow<List<Teacher>>(emptyList())
val teachersState = _teachersState.asStateFlow() }

// In your UI LazyColumn { items(viewModel.studentsState.collectAsState().value) { student -> // Only recomposes when students change } }

  1. Use remember with key:

@Composable fun MyScreen(state: ViewState) { val students by remember(state.students) { mutableStateOf(state.students) } val teachers by remember(state.teachers) { mutableStateOf(state.teachers) }

LazyColumn {
    items(students) { student ->
        // Only recomposes when students change
    }
} }

The best approach depends on your specific needs:

Use approach #1 if you want to keep single state but need derived values Use approach #2 if the lists are updated independently and you want clear separation Use approach #3 if you want a simpler solution and don't need the overhead of StateFlow

Reasons:
  • Long answer (-1):
  • Has code block (-0.5):
  • User mentioned (1): @Composable
  • Low reputation (1):
Posted by: Abhinay Gowda