Here are some points I want to share about the code:
1. Null Pointer Exception: The error indicates that array[mid] is null when the compareTo method is invoked, resulting in the exception. This implies that there may be elements in your array that are not initialized.
2.Using natural boolean: You don't necessarily need a natural boolean to distinguish between Comparable and Comparator. You can check if a Comparator is provided (e.g., cmp != null) and use it, or default to Comparable if no Comparator is available.
Code improvements:
import java.util.Comparator;
public class BinarySearch<E> {
private E[] array;
private Comparator<? super E> cmp;
private int maxIndex;
public BinarySearch(E[] array, Comparator<? super E> cmp) {
this.array = array;
this.cmp = cmp;
this.maxIndex = array.length - 1;
}
//The correct code
@SuppressWarnings("unchecked")
public int binarySearch(E item) {
if (item == null) {
throw new IllegalArgumentException("Item to search cannot be null.");
}
int start = 0;
int end = maxIndex;
while (start <= end) {
int mid = (start + end) / 2;
if (array[mid] == null) {
throw new NullPointerException("Array contains null elements at index " + mid);
}
int comparison;
if (cmp != null) {
comparison = cmp.compare(item, array[mid]);
} else if (item instanceof Comparable) {
comparison = ((Comparable<? super E>) item).compareTo(array[mid]);
} else {
throw new IllegalStateException("Item is not Comparable, and no Comparator was provided.");
}
if (comparison == 0) {
return mid;
} else if (comparison < 0) {
end = mid - 1;
} else {
start = mid + 1;
}
}
return -1;
}
public static void main(String[] args) {
Integer[] arr = {1, 2, 3, 4, 5, 6, 7, 8, 9};
BinarySearch<Integer> search = new BinarySearch<>(arr, null);
int index = search.binarySearch(5);
System.out.println("Index of 5: " + index);
}
}