Lets Debug this step by step:

1. int i = 0; → i is initialized to 0. so i contains the value 0

2. ++i → Pre-increment happens, so nows i becomes 1.

3. i + ++i → Substituting values:

4. i is 0 (original value before pre-increment).

5. ++i makes i = 1, so now ++i returns 1.

6. i + ++i = 0 + 1 = 1.

7. i = 1 (final value).

8. System.out.println(i); prints 1.

Your Next question Does the increment change the memory address?

• No, in Java, int is a primitive type, which means it is stored directly in memory, not as a reference. The value of i is updated in the same memory location. When you write ++i, it modifies the value in place.