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我也遇到了类似的问题，我尝试写一个i18n.t函数，支持t('xxx')调用，支持t.xxx直接取值，支持txxx标签函数调用，同时不希望原型链上任何方法或属性干扰typescript的类型推导列表。我查阅了社区的一些问题，这是我的解决方案。

const Message = <const>{__proto__: null, site_name: 'my site name', more: 'More Q&A' }
declare abstract class NonPrototype extends null {
  private apply(): never
  private bind(): never
  private call(): never
private arguments: never
  private caller: never
  private length: never
  private name: never
  private prototype: never

  private hasOwnProperty: never
  private isPrototypeOf: never
  private propertyIsEnumerable: never
  private toLocaleString: never
  private valueOf: never
  private ['constructor']: never
}
interface Translate extends Message, NonPrototype {
  <const K extends keyof Message>(key: K): Message[K]
  (key: TemplateStringsArray): string
}
export const t: Translate = (k => messages[k]) as any
window.t = t
Reflect.setPrototypeOf(t, messages)
Reflect.deleteProperty(t, 'length')
Reflect.deleteProperty(t, 'name')

t.site_name // my site name
t.more // More Q&A
t.unknown_key // error
t('site_name') // my site name
t('more') // More Q&A
t('unknown_key') // error
var key: string = 'site_name'
var value = t[key] // any
t.apply // error
t.bind // error
t.toString // error
t.hasOwnProperty // error
t.constructor // error
t.__proto__ // error
t[Symbol.iterator] // any
new t // error

/**
 * ## try read property, the type list is
 * Symbol
 * site_name
 * more
 *
 * ## first item is Symbol, i can’t remove it 😡
 */
// t.

/**
 * ## try call translate function, the list is
 * site_name
 * more
 *
 * ## there is no any other property 🥰
 */
// t('')

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