79479987

Date: 2025-03-03 00:57:49
Score: 0.5
Natty:
Report link

A solution that never caused the error again for me was to use:

import java.util.Scanner;

String arbritraryString ="";
int arbritraryInteger =0;
boolean temporaryCondition =false;
Scanner keyboard =new Scanner(System.in);

do{
    try{
        arbritraryString =keyboard.nextLine();
        arbritraryInteger =Integer.parseInt(arbritraryString);
        /*
        The rest of your code
        */
        temporaryCondition =false;
    }catch(NumberFormatException e){System.err.println("error"); temporaryCondition =true;}
}while(temporaryCondition);
Reasons:
  • Long answer (-0.5):
  • Has code block (-0.5):
  • Unregistered user (0.5):
  • Low reputation (1):
Posted by: user29862720