79527528

Date: 2025-03-22 13:41:20
Score: 1.5
Natty:
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Another elegant solution to this problem -

select m.firstname, m.surname,
round(sum(b.slots)/2,-1) as hours,
rank() over(order by round(sum(b.slots)/2,-1) desc) rank
from cd.members m join cd.bookings b
using (memid)
group by memid
order by rank, 2, 1
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Posted by: user30023500