79655435

Date: 2025-06-06 05:24:39
Score: 2
Natty:
Report link

Usually it's a reference, but it can be a copy as well. Check std::atomic.operator=.

If you don't have a good reason for copy, then just define the return type as a reference.

Reasons:
  • Low length (1):
  • No code block (0.5):
  • Low reputation (0.5):
Posted by: HQW.ang