79692610

Date: 2025-07-07 09:28:01
Score: 1
Natty:
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Yes, it fine, Better you can use regular expressions Match headers with optional content following

headerpattern = r"\*\*(H\d): (.*?)\*\*"

headers = re.findall(header_pattern, test)

Reasons:
  • Whitelisted phrase (-1.5): you can use
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  • Low reputation (1):
Posted by: Arpan Gautam