79705350

Date: 2025-07-17 20:13:15
Score: 3.5
Natty:
Report link

<?php

$loginUrl = $instagram->getLoginUrl();

echo "<a class='button' href='$loginUrl'>Sign in with Instagram</a>";

?>

Reasons:
  • Low length (1):
  • No code block (0.5):
  • Contains question mark (0.5):
  • Unregistered user (0.5):
  • Low reputation (1):
Posted by: chelcy